"using a variable outside of the while loop (scope)" Answer’s


You could try to define the variable before the loop, e.g.

$report = "";
while ($row = mysql_fetch_array($result)) {
    $report .= "a"."b".$row["prevDOCid"]+1;
echo $report;

I hope this helps you!

Edit Use .= not +=

Wednesday, March 31, 2021
answered 10 Months ago
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