Asked  7 Months ago    Answers:  5   Viewed   41 times

youtube.xml

<feed xmlns="http://www.w3.org/2005/Atom" xmlns:media="http://search.yahoo.com/mrss/" xmlns:openSearch="http://a9.com/-/spec/opensearchrss/1.0/" xmlns:gd="http://schemas.google.com/g/2005" xmlns:yt="http://gdata.youtube.com/schemas/2007">  

    <entry>
        ...
        <yt:duration seconds="1870"/>
        ...
    </entry>

</feed>

update_videos.php

$source = 'youtube.xml';

// load as file
$youtube = new SimpleXMLElement($source, null, true);

foreach($youtube->entry as $item){
    //title works
    echo $item->title;

    //now how to get seconds? My attempt...
    $namespaces = $item->getNameSpaces(true);
    $yt = $item->children($namespaces['yt']);
    $seconds = $yt->duration->attributes();
    echo $seconds['seconds'];
    //but doesn't work :(
}   

 Answers

65

So I found a way to do it using xpath, is this the best way or is there a way that's consistent with my code in the question? Just out of curiosity.

$source = 'youtube.xml';

// load as file
$youtube = new SimpleXMLElement($source, null, true);
$youtube->registerXPathNamespace('yt', 'http://gdata.youtube.com/schemas/2007');

$count = 0;
foreach($youtube->entry as $item){

    //title works
    echo $item->title;

    $attributes = $item->xpath('//yt:duration/@seconds');
    echo $attributes[$count]['seconds'];
    $count++;
}
Wednesday, March 31, 2021
 
jeremyharris
answered 7 Months ago
99

You are probably looking for get_attribute(). An example is shown here as well

def test_chart_renders_from_url(self):
    url = 'http://localhost:8000/analyse/'
    self.browser.get(url)
    org = driver.find_element_by_id('org')
    # Find the value of org?
    val = org.get_attribute("attribute name")
Tuesday, June 1, 2021
 
sassy_geekette
answered 5 Months ago
76

Usually, people use children().

$rss = simplexml_load_string(
    '<?xml version="1.0" encoding="utf-8"?>
    <rss version="2.0" xmlns:moshtix="http://www.moshtix.com.au">
        <channel>
            <link>qweqwe</link>
            <moshtix:genre>asdasd</moshtix:genre>
        </channel>
    </rss>'
);

foreach ($rss->channel as $channel)
{
    echo 'link: ', $channel->link, "n";
    echo 'genre: ', $channel->children('moshtix', true)->genre, "n";
}
Tuesday, June 8, 2021
 
Whakkee
answered 5 Months ago
29

You could work with XPath and registerXPathNamespace():

$xml->registerXPathNamespace("georss", "http://www.georss.org/georss");
$xml->registerXPathNamespace("gml", "http://www.opengis.net/gml");
$pos = $xml->xpath("/georss:where/gml:Point/gml:pos");

From the docs, emphasis mine:

registerXPathNamespace […] Creates a prefix/ns context for the next XPath query.

More ways to handle namespaces in SimpleXML can be found here, for example:
Stuart Herbert On PHP - Using SimpleXML To Parse RSS Feeds

Tuesday, June 15, 2021
 
Classified
answered 5 Months ago
86
var tds = document.getElementById("ctl00_ContentPlaceHolder1_Jobs_dlItems_ctl01_a").getElementsByTagName("td");
time = tds[0].firstChild.value;
address = tds[3].firstChild.value;
Friday, September 24, 2021
 
zIs
answered 1 Month ago
zIs
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