Asked  7 Months ago    Answers:  3   Viewed   38 times

I've spend over 6 hours to find an exception or a special character to find in my code but I couldn't. I checked every similar messages in here.

I'm sending the form with magnific popup. First I'm using inline popup to open my form than I'm sending all inputs to main.js to validate.

So, I just need a third-eye.

I've got: index.html, register.php, main.js

Here's the code




Here goes the error messages

JSON Output json

Chrome Console:


Firefox console : firefox

What am i missing?



The fact the character is a < make me think you have a PHP error, have you tried echoing all errors.

Since I don't have your database, I'm going through your code trying to find errors, so far, I've updated your JS file

$("#register-form").submit(function (event) {

    var entrance = $(this).find('input[name="IsValid"]').val();
    var password = $(this).find('input[name="objPassword"]').val();
    var namesurname = $(this).find('input[name="objNameSurname"]').val();
    var email = $(this).find('input[name="objEmail"]').val();
    var gsm = $(this).find('input[name="objGsm"]').val();
    var adres = $(this).find('input[name="objAddress"]').val();
    var termsOk = $(this).find('input[name="objAcceptTerms"]').val();

    var formURL = $(this).attr("action");

    if (request) {
        request.abort(); // cancel if any process on pending

    var postData = {
        "objAskGrant": entrance,
        "objPass": password,
        "objNameSurname": namesurname,
        "objEmail": email,
        "objGsm": parseInt(gsm),
        "objAdres": adres,
        "objTerms": termsOk

        console.log("Data: " + data + "nStatus: " + status);


PHP Edit:

 if (isset($_POST)) {

    $fValid = clear($_POST['objAskGrant']);
    $fTerms = clear($_POST['objTerms']);

    if ($fValid) {
        $fPass = clear($_POST['objPass']);
        $fNameSurname = clear($_POST['objNameSurname']);
        $fMail = clear($_POST['objEmail']);
        $fGsm = clear(int($_POST['objGsm']));
        $fAddress = clear($_POST['objAdres']);
        $UserIpAddress = "hidden";
        $UserCityLocation = "hidden";
        $UserCountry = "hidden";

        $DateTime = new DateTime();
        $result = $date->format('d-m-Y-H:i:s');
        $krr = explode('-', $result);
        $resultDateTime = implode("", $krr);

        $data = array('error' => 'Yükleme S?ras?nda Hata Olu?tu');

        $kayit = "INSERT INTO tbl_Records(UserNameSurname, UserMail, UserGsm, UserAddress, DateAdded, UserIp, UserCityLocation, UserCountry, IsChecked, GivenPasscode) VALUES ('$fNameSurname', '$fMail', '$fGsm', '$fAddress', '$resultDateTime', '$UserIpAddress', '$UserCityLocation', '$UserCountry', '$fTerms', '$fPass')";
        $retval = mysql_query( $kayit, $conn ); // Update with you connection details
            if ($retval) {
                $data = array('success' => 'Register Completed', 'postData' => $_POST);

        } // valid ends
    }echo json_encode($data);
Wednesday, March 31, 2021
answered 7 Months ago

Simply change

var respons = jQuery.parseJSON(response);


var respons = response;


If the configuration of your AJAX call is having dataType: json you'll get a JavaScript object so it's no longer necessary to use JSON.parse().

Saturday, May 29, 2021
answered 5 Months ago

If you're doing the $.parseJSON(data) in an ajax success handler Since you're doing the $.parseJSON(data) in an ajax success handler, the problem is almost certainly that jQuery has already parsed it for you. jQuery will look at the Content-Type of the response and, if it's application/json, it will parse it, and provide the parsed result to your success handler. The first thing that will happen if you pass that into $.parseJSON will be that it will get converted back to a string ("[object Object]", in your case), which $.parseJSON will then fail to parse.

Just use data as-is, it's already an object, thanks to the automatic parsing:

$(document).ready(function() {
    $('#branchAndSubjects').click(function() {
        $.post('/findBranchAndSubjects', {
            roll: roll,
            _token: "{{csrf_token()}}"
        }, function(data) {
            console.log(data.year);             // 3
            console.log(data.subjects.length);  // 4
            console.log(data.subjects[0].name); // Control Systems
Sunday, August 22, 2021
answered 2 Months ago
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