Asked  7 Months ago    Answers:  5   Viewed   92 times

I want to be able to convert big ints into their full string derivatives.

For example.

$bigint = 9999999999999999999;
$bigint_string = (string) $bigint;


string(7) "1.0e+19"

but i need

string(19) "9999999999999999999"

Please don't tell me that I should just originally set the $bigint value as a string. That is not an option. I really am stuck and don't know if it is even possible?



You actually should ensure that you type what you mean:

$bigint = 9999999999999999999;

Is not a PHP integer but float:


If you would have done

$bigint = (int) 9999999999999999999;

You would have set an integer in fact, but it would not be the number you might have expected:


It's no problem at all to turn that into string as you might have guessed. So take care when you write numbers into code that you actually write what you mean.

See this line again:

$bigint = 9999999999999999999;

try to understand what you have actually written. It's not an integer at all because PHP will turn it into a float. See Example #4 Integer overflow on a 64-bit system in the integer manual page.

If you need higher precision, checkout GNU Multiple Precision, it might have what you're looking for. However, this won't change how to write numbers in PHP:

$bigint = gmp_init("9999999999999999999");
$bigint_string = gmp_strval($bigint);
var_dump($bigint, $bigint_string);


resource(4) of type (GMP integer)
string(19) "9999999999999999999"
Wednesday, March 31, 2021
answered 7 Months ago

A regex would be simplest:

$input = 'foo_left.jpg';
if(!preg_match('/_(left|right|center)/', $input, $matches)) {
    // no match

$pos = $matches[0]; // "_left", "_right" or "_center"

See it in action.


For a more defensive-minded approach (if there might be multiple instances of "_left" and friends in the filename), you can consider adding to the regex.

This will match only if the l/r/c is followed by a dot:

preg_match('/(_(left|right|center))./', $input, $matches);

This will match only if the l/r/c is followed by the last dot in the filename (which practically means that the base name ends with the l/r/c specification):

preg_match('/(_(left|right|center))\.[^\.]*$/', $input, $matches);

And so on.

If using these regexes, you will find the result in $matches[1] instead of $matches[0].

Wednesday, March 31, 2021
answered 7 Months ago

printf and friends will do this:

$awb = 2.01421700079E+14;
$str = sprintf("%d", $awb);


string(15) "201421700079000"

There obviously isn't enough information in your original number to get any more precision than that.

Saturday, May 29, 2021
answered 5 Months ago

Use the strconv package's Itoa function.

For example:

package main

import (

func main() {
    t := strconv.Itoa(123)

You can concat strings simply by +'ing them, or by using the Join function of the strings package.

Wednesday, June 9, 2021
answered 5 Months ago

This can't work properly. Stored with Unicode there are many more Characters than with ANSI. So if you "convert" to ANSI, you will loose lots of charackters.

You can use Unicode (UTF-8) charset with htmlentities:

string htmlentities ( string $string [, int $flags = ENT_COMPAT [, string $charset [, bool $double_encode = true ]]] )

htmlentities($myString, ENT_COMPAT, "UTF-8"); should work.

Thursday, August 5, 2021
answered 3 Months ago
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