Asked  7 Months ago    Answers:  5   Viewed   162 times

I want to remove all empty strings from a list of strings in python.

My idea looks like this:

while '' in str_list:

Is there any more pythonic way to do this?



I would use filter:

str_list = filter(None, str_list)
str_list = filter(bool, str_list)
str_list = filter(len, str_list)
str_list = filter(lambda item: item, str_list)

Python 3 returns an iterator from filter, so should be wrapped in a call to list()

str_list = list(filter(None, str_list))
Tuesday, June 1, 2021
answered 7 Months ago
>>> 'QH QD JC KD JS'.split()
['QH', 'QD', 'JC', 'KD', 'JS']


Return a list of the words in the string, using sep as the delimiter string. If maxsplit is given, at most maxsplit splits are done (thus, the list will have at most maxsplit+1 elements). If maxsplit is not specified, then there is no limit on the number of splits (all possible splits are made).

If sep is given, consecutive delimiters are not grouped together and are deemed to delimit empty strings (for example, '1,,2'.split(',') returns ['1', '', '2']). The sep argument may consist of multiple characters (for example, '1<>2<>3'.split('<>') returns ['1', '2', '3']). Splitting an empty string with a specified separator returns [''].

If sep is not specified or is None, a different splitting algorithm is applied: runs of consecutive whitespace are regarded as a single separator, and the result will contain no empty strings at the start or end if the string has leading or trailing whitespace. Consequently, splitting an empty string or a string consisting of just whitespace with a None separator returns [].

For example, ' 1 2 3 '.split() returns ['1', '2', '3'], and ' 1 2 3 '.split(None, 1) returns ['1', '2 3 '].

Tuesday, June 8, 2021
answered 6 Months ago
var arr = ["I", "am", "", "still", "here", "", "man"]
// arr = ["I", "am", "", "still", "here", "", "man"]
arr = arr.filter(Boolean)
// arr = ["I", "am", "still", "here", "man"]

filter documentation

// arr = ["I", "am", "", "still", "here", "", "man"]
arr = arr.filter(v=>v!='');
// arr = ["I", "am", "still", "here", "man"]

Arrow functions documentation

Saturday, June 12, 2021
answered 6 Months ago

Using RegExp and ^ to ensure it is the prefix and not just somewhere in the string:

var arr = ['a1', 'a2', 'a54a'];
for(var i = 0, len = arr.length; i < len; i++) {
    arr[i] = arr[i].replace(/^a/, '');
arr; // '1,2,54a' removing the 'a' at the begining
Thursday, August 12, 2021
answered 4 Months ago

I would do

matches = [ s for s in states if s in postal_addr ]

Then, if you want to get the string from the postal address:

import re
if matches:
    extracted = re.findall( matches[0],  postal_addr)[0]

EDIT: ..but this won't work for city/state combos where the city name contains a different state, for example if postal_adr = '1 Arrowhead Dr, Kansas City, Missouri 64129' and states = ["New York", "California", "Nebraska", "Idaho", "Missouri", "Kansas"] etc. In this case

import re
if matches:
    extracted = [(, postal_addr).start() , m) for m in matches ]
    extracted = sorted( extracted )[-1][1]
Tuesday, August 31, 2021
answered 3 Months ago
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